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7x^2-7=273
We move all terms to the left:
7x^2-7-(273)=0
We add all the numbers together, and all the variables
7x^2-280=0
a = 7; b = 0; c = -280;
Δ = b2-4ac
Δ = 02-4·7·(-280)
Δ = 7840
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7840}=\sqrt{784*10}=\sqrt{784}*\sqrt{10}=28\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-28\sqrt{10}}{2*7}=\frac{0-28\sqrt{10}}{14} =-\frac{28\sqrt{10}}{14} =-2\sqrt{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+28\sqrt{10}}{2*7}=\frac{0+28\sqrt{10}}{14} =\frac{28\sqrt{10}}{14} =2\sqrt{10} $
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